WebMar 5, 2024 · You can use try except with IndexError to fix the problem try: date = re.findall (regex_pattern) [0].replace ('\/', '/') except IndexError: print ("Date not found!") exit () Share Improve this answer Follow answered Mar 5 at 19:46 tomerar 755 3 9 Add a comment Not the answer you're looking for? Browse other questions tagged python WebApr 22, 2024 · You're getting this error because of these lines: for name in names: taskcount.pop (0) taskcount = list (unique_everseen (taskcount)) Removing these …
python - IndexError: list index out of range in opencv - Stack Overflow
WebJul 21, 2024 · browser = webdriver.PhantomJS ("phantomjs") browser.get (url) while True: time.sleep (pause) newHeight = browser.execute_script ("return document.body.scrollHeight") print newHeight browser.find_elements_by_class_name ('alt') [0].click () python selenium selenium-webdriver Share Follow asked Jul 20, 2024 at … WebJul 16, 2024 · cv = [ [] for _ in range (len (models))] it has an empty list for each model. In the loop, however, you go over enumerate (zip (models, params)) which has only two elements, since your params list has two elements (because list (zip (x,y)) has length equal to min (len (x),len (y) ). fly til wagrain
python - when using contractions.fix on the dataframe in pandas …
WebDec 19, 2024 · Solution for IndexError python list index out of range Error The best way to avoid this problem is to use the len (list)-1 format to limit the indexation limits. This way you can not only avoid the indexing problems but also make your program more dynamic. 1. Lists are indexed from zero: WebApr 18, 2024 · Screenshot of the Dataset, I want to run contractions.fix on comments column The screenshot of the code and the error is thrown: This is my code to run contractions.fix: rws ["expanded_words"]=rws ['comments'].apply (lambda x: [contractions.fix (word) for word in x.split ()]) python pandas dataframe nltk Share … WebBut the right way to copy a object in python is using python module copy - Shallow and deep copy operations. l= [1,2,3,0,0,1] for i in range (0,len (l)): if l [i]==0: l.pop (i) If instead of this, import copy l= [1,2,3,0,0,1] duplicate_l = copy.copy (l) for i in range (0,len (l)): if l [i]==0: m.remove (i) l = m fly til zambia